Buscar
Estás en modo de exploración. debe iniciar sesión para usar MEMORY

   Inicia sesión para empezar


Por supuesto:

GCSE Chemistry 2020-2022 OCR Gateway

» Iniciar este curso
(Practica preguntas similares gratis)
Pregunta:

Muhammad puts 8.14g of Zinc Oxide in a Crucible with 0.30g of Carbon, and was Heated until they reacted. Knowing that the Balance Equation is 2ZnO + C = CO² + 2Zn, Find the Limiting Reactant here

Autor: go kys



Respuesta:

1. First divide the Mass of each Substance that was Reacted [The Reactants] by its Ar or Mr to find the number of Moles [ZnO= 8.14/81.4=0.10] [C=0.3/12 = 0.025] 2. Divide by the Smallest number of Moles [0.025 here] [0.10/0.025 = 4.0] [0.025/0.025 = 1] 3. Using the Rations the Moles, and Compare them with the Products of the Balanced Equation [Here. ZnO and C React in a ration of 2:1. These masses show that there is a 4:1 ratio of ZnO to C. This would mean that Carbon is the Limiting Factor]


0 / 5  (0 calificaciones)

1 answer(s) in total

Autor

go kys
go kys