Buscar
Estás en modo de exploración. debe iniciar sesión para usar MEMORY

   Inicia sesión para empezar

Physics - Heat and Temperature

Year 11 ATAR


🇬🇧
In Inglés
Creado:
Physics - Heat and Temperature


Public
Creado por:
Lauren Noack


0 / 5  (0 calificaciones)



» To start learning, click login

1 / 25

[Front]


- all matter (s/l/g) is made up of small particles, atoms or molecules - All particles are in constant motion - No kinetic energy is gained or lost during collisions between particles - there are forces of attraction and repulsion between particles within a material - the distance between particles in a gas are large compared to the size of the particles
[Back]


Kinetic Particle Model Assumptions

Practique preguntas conocidas

Manténgase al día con sus preguntas pendientes

Completa 5 preguntas para habilitar la práctica

Exámenes

Examen: pon a prueba tus habilidades

Pon a prueba tus habilidades en el modo de examen

Aprenda nuevas preguntas

Modos dinámicos

InteligenteMezcla inteligente de todos los modos
PersonalizadoUtilice la configuración para ponderar los modos dinámicos

Modo manual [beta]

El propietario del curso no ha habilitado el modo manual
Modos específicos

Aprende con fichas
elección múltipleModo de elección múltiple
Expresión oralResponde con voz
EscrituraModo de solo escritura

Physics - Heat and Temperature - Marcador

1 usuario ha completado este curso

Ningún usuario ha jugado este curso todavía, sé el primero


Physics - Heat and Temperature - Detalles

Niveles:

Preguntas:

26 preguntas
🇬🇧🇬🇧
°C = 273.15K K = -273.15°C
Converting between degrees Celsius and Kelvin
Q = ? m = 135 L = 135 kg c = 4200 J kg-1 K-1 ΔT = 70 – 20 = 50 K Q = mcΔT = 135 x 4200 x 50 = 28 350 000 J = 28 MJ
A hot water tank contains 135 L of water. Initially the water is at 20 ˚C. Calculate the amount of energy that must be transferred to the water to raise the temperature to 70˚C.
Q = ? m = 2.5 L = 2.5 kg Lwater = 3.34x10^5 J kg-1 Q = 8.35x10^2 kJ
How much energy must be removed from 2.5 L of water at 0˚C to produce a block of ice at 0 ˚C. Express your answer in kJ.
Q = ? Q = ? m = 50 ml = 50 g = 0.05 kg m = 0.05 kg c = 4180 J kg-1 K-1 L = 22.5 x 10^5 J kg-1 ΔT = 100 -20 = 80 K Q = 16 800 J Q = 112 500 J total Q = 129 300 J
50 ml of water is heated from a room temperature of 20 ˚C to its boiling point at 100 ˚C . It is boiled at this temperature until it is completely evaporated. How much energy in total was required to raise the temperature and boil the water?
YES
Fridges